DISEQUAZIONI NUMERICHE RAZIONALI

 $\frac{{x}^{2}-4x}{\left(3-x\right)\left({x}^{2}+x+2\right)}\le 0$ $\frac{8x-2{x}^{3}}{{x}^{2}+2x-3}\le 0$ $\frac{1}{x+2}>\frac{1}{x}-\frac{1}{x+1}$ $\frac{1}{x}+\frac{1}{x-2}\ge \frac{2}{{x}^{2}-2x}$ $-\frac{1}{{x}^{2}+x-6}\le \frac{1}{1-{x}^{2}}$ $\frac{1}{{x}^{2}-x}-\frac{1}{x}\ge \frac{2}{x-1}$ $\frac{{x}^{3}-x}{{x}^{2}+x-6}\ge 0$ $\frac{{x}^{4}+4{x}^{2}-5}{{x}^{3}\left(9x-{x}^{2}\right)}>0$