EQUAZIONI ESPONENZIALI
2
x
+
2
x
+
1
=
3
⋅
2
3
−
x
2^x + 2^{ x+1 }= 3 cdot 2^{ 3-x }
3
x
+
1
⋅
2
=
2
x
−
1
⋅
3
3^{ x+1 } cdot 2 = 2^{ x-1 } cdot 3
1
4
(
3
x
+
3
x
+
1
)
=
3
1
−
x
{ 1 } over { 4 } ( 3^x + 3^{x+1} )= sqrt{ 3^{1-x }}
5
x
+
1
−
5
x
=
3
x
5^{ x+1 } - 5^x = 3^x
5
x
⋅
9
−
5
x
+
1
=
5
2
x
+
1
⋅
4
5^x cdot 9 - 5^{x+1} = 5^{ 2x+1 } cdot 4
(
2
)
x
3
=
(
3
)
x
2
( 2 )^{x^3}=( 3 )^{ x^2 }
2
x
+
1
+
2
x
+
3
=
20
2
x
−
5
2^{ x+1 }+ 2^{ x+3 }= 20 sqrt{ 2^{x-5 }}
2
x
+
3
+
2
x
+
1
=
3
x
+
3
x
−
2
2^{ x+3 } + 2^{ x+1 }=3^x + 3^{ x-2 }
3
x
+
2
+
7
⋅
3
x
=
4
x
+
1
+
5
⋅
4
x
3^{ x+2 } + 7 cdot 3^x = 4^{ x+1 } + 5 cdot 4^x
|
e
x
−
1
|
=
e
2
x
abs{ e^x - 1 }=e^{ 2x }
