1
4
(
3
x
+
3
x
+
1
)
=
3
1
−
x
1
4
(
3
x
+
3
⋅
3
x
)
=
3
1
−
x
2
1
4
⋅
3
x
⋅
(
1
+
3
)
=
3
1
2
⋅
3
−
x
2
3
x
=
3
1
2
⋅
3
−
x
2
3
x
⋅
3
x
2
=
3
1
2
3
x
2
+
x
=
3
1
2
3
3
x
2
=
3
1
2
3
3
x
=
3
1
3
x
=
1
x
=
1
3
{ 1 } over { 4 } ( 3^x + 3^{x+1} )= sqrt{ 3^{1-x }} newline
{ 1 } over { 4 } ( 3^x + 3 cdot 3^{x} )= { 3^{{1-x} over 2 }} newline
{ 1 } over { 4 } cdot 3^x cdot (1+ 3)= { 3^{{1} over 2 }} cdot { 3^-{{x} over 2 }} newline
3^x = { 3^{{1} over 2 }} cdot { 3^-{{x} over 2 }} newline
3^x cdot { 3^{{x} over 2 }}= { 3^{{1} over 2 }} newline
{ 3^{{x} over 2 +x}}= { 3^{{1} over 2 }} newline
{ 3^{{3x} over 2}}= { 3^{{1} over 2 }} newline
{ 3^{{3x} }}= 3^1 newline
3x= 1 newline
x= 1 over 3