0 1 1 1+ x 2 x = [ arctg(x) ] 0 1 =arctg(1)= π 4 π =4 0 1 1 1+ x 2 x


Ampiezza del sottointervallo: ∆x= (b - a)/n= 1/10= 0.1


  • Metodo dei rettangoli

0 1 1 1+ x 2 x = 1 10 [ f(0)+f(0.1)+f(0.2)+f(0.3)+f(0.4)+f(0.5)+f(0.6)+f(0.7)+f(0.8)+f(0.9) ]= 

= 1 10 ( 1 1+ 0 2 + 1 1+0. 1 2 + 1 1+0. 2 2 + 1 1+0. 3 2 + 1 1+0. 4 2 + 1 1+0. 5 2 + 1 1+0. 6 2 + 1 1+0. 7 2 + 1 1+0. 8 2 + 1 1+0. 9 2 )=0.809981497
π =4 0 1 1 1+ x 2 x =40.809981497=3.239925988


  • Metodo dei trapezi

0 1 1 1+ x 2 x = 1 10 [ f(0)+f(1) 2 +f(0.1)+f(0.2)+f(0.3)+f(0.4)+f(0.5)+f(0.6)+f(0.7)+f(0.8)+f(0.9) ]=
= 1 10 [ 1 1+ 0 2 + 1 1+ 1 2 2 + 1 1+0. 1 2 + 1 1+ 0.2 2 + 1 1+0. 3 2 + 1 1+ 0.4 2 + 1 1+ 0.5 2 + 1 1+ 0.6 2 + 1 1+ 0.7 2 + 1 1+ 0.8 2 + 1 1+ 0.9 2 ]=0.7849814972
π =4 0 1 1 1+ x 2 x =40.7849814972=3.139925989


  • Metodo delle parabole
0 1 1 1+ x 2 x = 1 3 1 10 { f(0)+f(1)+2[ f(0.2)+f(0.4)+f(0.6)+f(0.8) ]+4[ f(0.1)+f(0.3)+f(0.5)+f(0.7)+f(0.9) ] }=
= 1 30 [ 1 1+ 0 2 + 1 1+ 1 2 +2( 1 1+0. 2 2 + 1 1+0. 4 2 + 1 1+0. 6 2 + 1 1+0. 8 2 )+4( 1 1+0. 1 2 + 1 1+0. 3 2 + 1 1+0. 5 2 + 1 1+0. 7 2 + 1 1+0. 9 2 ) ]=0.7853981535
π =4 0 1 1 1+ x 2 x =40.7853981535=3.141592614