The position of the maximum interference is found with the formula:

$y_{max}=m\cdot \frac{\lambda }{d}\cdot L$

(assuming that the screen is away from the two slits).
The position of the minimum of interference is found with the formula:

$y_{min}=\frac{2n-1}{2}\cdot \frac{\lambda }{d}\cdot L$

For the yellow we have the maximum in:

$y_g=m\cdot \frac{{\lambda }_g}{d}\cdot L$

while for the red we have miminum in:  

$y_r=\frac{2n-1}{2}\cdot \frac{{\lambda }_r}{d}\cdot L$

In unit L / d for the yellow we derive the positions of the maximum yellow : y_g= 576, 1152, 1728, 2304, 2880, ...  and of the minimum red: y_r= 336, 1008, 1680, 2352, ....
We can see that the third bright fringe yellow (except the center) is positioned approximately at the third minimum of red.