Applicando le Trasformazioni di Lorentz:    $x=\frac{x\text{'}+vt\text{'}}{\sqrt{1-{\beta }^2}}=\frac{60+0.6\cdot 3\cdot 10^{8}80\cdot 10^{-9}}{\sqrt{1-0.6^2}}= \frac{74.4}{0.8}=93 m$e  $t=\frac{t\text{'}+\frac{v}{c^2}x\text{'}}{\sqrt{1-{\beta }^2}}=\frac{80\cdot 10^{-9}+\frac{0.6}{3\cdot 10^8}\cdot 60}{\sqrt{1-0.6^2}}=\frac{200\cdot 10^{-9}}{0.8}=\mathrm{250 }ns$